apoc.map.fromValues Function APOC Core apoc.map.fromValues([key1,value1,key2,value2,…]) Signature apoc.map.fromValues(values :: LIST? OF ANY?) :: (MAP?) Input parameters Name Type Default values LIST? OF ANY? null Usage Examples The following creates a map from alternating keys and values in a list: RETURN apoc.map.fromValues([ "name", "Cristiano Ronaldo", "age", date("1985-02-05") ]) AS output; Table 1. Results Output { "name": "Cristiano Ronaldo", "age": "1985-02-05" } apoc.map.fromPairs apoc.map.get