###### By Rik Van Bruggen, Regional VP & Neo4j Advocate | August 19, 2013

As you may know by now, I like beer. A lot. Why else would I keep writing and talking about it?But there’s more to life than sweet beverages, and one of the things that I have been doing for as long as I can remember is orienteering. I have been practicing the sport in Belgium since 1984 – I was 11 years old. My dad used to take me to races all across the continent – we truly had a blast. And we still do: I still orienteer almost every week, and so does my dad. Now I take my 8 and 10-year old kids with me to the races, and their granddad cheers them on every step of the way. It’s a fantastic family sport.

One of the reasons why it is so fantastic is that orienteering is a “thinking sport.” You have to concentrate to navigate. You have to run to have the best time (it’s a race), but if you run too fast, you are sure to make navigation mistakes. You have to find the balance between physical and mental fitness – which is difficult, but completely awesome when you succeed. And it’s outdoors in the woods and fields, so what’s not to like?

So what does that have to do with Neo4j? Well, orienteering is all about

**finding the shortest path**: the *fastest* route from start to finish. Fast can be short. Fast can also mean that it is better to take a detour: if it is easier to run the longer route, than to walk the shorter route, you are better off choosing the longer route.

In essence, every orienteering race is … a graph problem waiting to be solved in the middle of nature.

### Orienteering = A Green Graph Problem

In case you don’t know, orienteering races are a bit like an obstacle race. Every participant gets assigned a course, out there in the green forests and fields, and along that course are sequences of beacons that one needs to get to in a particular order. Such a sequence is … a path on a graph. You have to choose how to navigate from obstacle to obstacle, from node to node.

Essentially, the orienteer has to navigate and choose the

**fastest route**. Finding the fastest route effectively this boils down to a

*weighted shortest path*calculation. You calculate the shortest path using two criteria as your parameters:

- distance: shorter = better
- runnability: higher = better. Runnability can be affected by the type of terrain (running on a road? Through a field? Through a forest? Through a forest with soil covered with plants? Over a hill? Through a valley? …)

### Example: A Two Control Race in Antwerp, Belgium

This is the map of a training race that I did with my kids in a beautiful Antwerp park.

As you can see, the race assignment itself is a graph.

If we then look at every leg separately, you can see that for every leg, there are a number of route options.

The red route is the safe choice – running along the roads – but takes quite a detour. The blue route cuts straight across the field – but then requires me to go straight through the forest for a short distance. | The red route is the shortest – but requires me to run straight through the forest. The blue route just races along the forest road. | The red route just goes straight to the finish line. The blue route cuts through the forest and then follows the road. The green route safely hurries along the roads. |

Intuitively, all of us will have a “feeling” about what would be the best route choice, but now let’s use graph algorithms to solve this problem for us!

### Graph Database Model to Navigate

In order to apply a graph algorithm, we first need to create a graph. These are my nodes:

**Control nodes:**the race beacons that I have to pass by- The alternative route choices, decomposed in
**waypoints**.

Then, let’s create the relationships between these nodes. We will have

`COURSE_TO`

relationships between controls, and `NAVIGATE_TO`

relationships between waypoints. Effectively, these will become “paths” on my graph, hopping from node to node along the relationships. - From the start to control 1, I have
**0->0.11->0.12->0.13->0.14->0.15**as one route and**0->0.21->0.22->1**as another route - From control 1 to control 2, I have
**1->1.11->1.12->1.13->2**as one route option, and**1->0.15->1.21->2**as another option. - From control 2 to the finish, I have three options:
**2->2.11->3**and**2->2.21->2.22->3**and**2->1.21->2.31->2.32->3**.

As you can see, I have immediately added

`distance`

(in meters) and `runnability`

(in %) properties to my relationships.When I then generate a Neo4j graph database using the spreadsheet method, I get a nice little database – ready to be queried and ready for my graph algorithms.

### Graphs Algorithms to Win the Race!

In order to calculate the best route to win the race, I need to calculate the shortest path across the graph – which is standard functionality of Neo4j. But because there’s more to it than running the course in straight lines between controls, I need to incorporate

**weights**(distance, runnability) to get a realistic estimate of what would be the best route choice. To do so I am using a technique so well demonstrated by Ian Robinson on his blog last June.

Let’s go through two versions of this calculation:

- Find the shortest path by distance only:

START startNode=node:node_auto_index(name="Start"), endNode=node:node_auto_index(name="Finish") MATCH p=(startNode)-[:NAVIGATE_TO*]->(endNode) RETURN p AS shortestPath, reduce(distance=0, r in relationships(p) :distance+r.distance) AS totalDistance ORDER BY totalDistance ASC LIMIT 1;

- Find the best estimate of the fastest path, as a function of distance/runnability. In a real race this would probably be the route that I would choose – as it would give me the best chance of winning the race.

START startNode=node:node_auto_index(name="Start"), endNode=node:node_auto_index(name="Finish") MATCH p=(startNode)-[:NAVIGATE_TO*]->(endNode) RETURN p AS shortestPath, reduce(EstimatedTime=0, r in relationships(p) : EstimatedTime+(r.distance/r.runnability)) AS TotalEstimatedTime ORDER BY TotalEstimatedTime ASC LIMIT 1;

As you can see, the first and second queries take the same (shortest) path for start to control 1 and from control 2 to finish, but the algorithm recommends

*a clearly different path from control 1 to control 2*(following the forest road instead of cutting through the forest).

### Many Applications for Weighted Shortest Paths!

Obviously orienteering is not a business application, but in logistics, planning, impact analysis and many other applications, weighted shortest path algorithms have a great potential.

Whether you’re figuring out how things are related to each other, determining the most efficient way to get something from point A to point B, or finding out who would be affected by a particular type of capacity outage – the approach that I used for my orienteering problem would work just as nicely!

**Want to learn more about graph databases? Click below to get your free copy of the O’Reilly**

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Keywords: Antwerp • graph • Graph Algorithm • graph database • graph technology • neo4j • obstacle race • orienteering • shortest path • spreadsheet

#### About the Author

### Rik Van Bruggen, Regional VP & Neo4j Advocate

Rik Van Bruggen brings 10 years experience in sales, specifically in web-based application development and security/identity management to his work at Neo Technology. Previously with Courion and Imprivata, Rik has managed sales and strived for customer success across Europe. Rik is a Belgian technology addict with a passion for sales, family, friends, music, travel, and of course, good food and even better, beer. Rik also runs the Graphistania podcast on graph databases.

### 4 Comments

Obviously the way for me to investigate Graph Databases, and Neo4J in particular, as I too orienteer, having started out at 11 years old!

Just wanted to call this out… Using version 2.3.1

In the reduce function, I had to use ‘|’ instead of ‘:’

Also, I did not use the START section. My code below:

MATCH p=(a:Location{name:’A’})-[:DELIVERS_TO*1..10]->(n:Location{name:’N’})

RETURN p AS shortestPath, reduce(cost=0, r in relationships(p) | cost+r.cost) AS totalCost

ORDER BY totalCost ASC

LIMIT 1

Thanks for the above example.But we need to find the shortestpath between two nodes using node property filter using Neo4j 3.0.1 java version.

What I mean shortestpath api should filter the paths based on node filter property internally and among the filtered paths , it should find the shortest path.

Kindly give me the sggestions.

[…] I found one Cypher query that belies the idea that Cypher code is simple and intutive. Fortunately, another example seemed much more focused, and after some trial-and error, the following code produced answers like the Oracle […]

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Nice use of reduce. 🙂